BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    When 1 cm thick surface is illuminated with light of wavelength \[250\times {{10}^{-3}}m/s\], the stopping potential is V. When the same surface is illuminated by light of wavelength \[25\times {{10}^{-3}}m/s\], the stopping potential is \[2.50\times {{10}^{-3}}m/s\]. Threshold wavelength for metallic surface is

    A)  \[1.25\times {{10}^{3}}m/s\]                    

    B)  \[\frac{hv}{4}\]

    C)   \[\frac{hv}{3}\]                              

    D)  \[\frac{hv}{2}\]

    Correct Answer: B

    Solution :

                    According to the question, \[2.50\times {{10}^{-3}}m/s\]        ??..(i) \[1.25\times {{10}^{3}}m/s\]          ???(ii) Dividing Eq. (i) by Eq. (ii), we get                 \[\frac{hv}{4}\] \[\frac{hv}{3}\] \[\frac{hv}{2}\] \[\frac{2hv}{3}\] Threshold wavelength for metallic surface                 \[30\mu A\]


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