A) \[64V,\,\,2\Omega \]
B) \[15min\]
C) \[20\text{ }min\]
D) \[7.5min\]
Correct Answer: A
Solution :
According to the question, the angle of minimum deviation \[{{\delta }_{m}}\] = Refracting angle Refractive index \[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \left( \frac{A}{2} \right)}\] \[=\frac{\sin \left( \frac{A+A}{2} \right)}{\sin \left( \frac{A}{2} \right)}=\frac{\sin A}{\sin \left( \frac{A}{2} \right)}\] \[=\frac{2\sin \left( \frac{A}{2} \right).\cos \left( \frac{A}{2} \right)}{\sin \left( \frac{A}{2} \right)}\] \[\frac{3}{2}=2\cos \left( \frac{A}{2} \right)\] \[\cos \left( \frac{A}{2} \right)=\frac{3}{4}\] \[\frac{A}{2}={{\cos }^{-1}}\left( \frac{3}{4} \right)\] \[A=2{{\cos }^{-1}}\left( \frac{3}{4} \right)\]
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