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BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    A square of side 3 cm is located at a distance of 25 cm from a concave of square, is at the axis of the mirror and the plane is normal to axis of mirror. The area enclosed by the image of the square is                 

    A)  \[25min\]                          

    B)  \[\frac{\omega M}{M+m}\]

    C)  \[\frac{\omega (M-2M)}{M+2m}\]                        

    D)  \[\frac{\omega (M-2M)}{M+2m}\]

    Correct Answer: A

    Solution :

                    Linear magnification \[m=\frac{l}{O}=\frac{f}{u-f}=\frac{10}{25-30}\] \[m=\frac{2}{3}\] Areal magnification \[={{m}^{2}}=\frac{4}{9}\] Area of image \[=\frac{4}{9}\times \] area of object                 \[=\frac{4}{9}\times {{(3)}^{2}}=4c{{m}^{2}}\]


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