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BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    Two resistors \[\frac{hv}{4}\]. and \[\frac{hv}{3}\]. are connected in series with 6V battery. The potential difference measured by voltmeter of \[\frac{hv}{2}\] across \[\frac{2hv}{3}\], resistor is

    A)  \[30\mu A\]                                     

    B)  \[90\mu A\]

    C)  \[4mA\]                             

    D)  \[2mA\]

    Correct Answer: B

    Solution :

                    Here, the resistances \[400\Omega \]and \[10000\Omega \]. are in parallel, their effective resistance \[{{R}_{P}}\] will be \[{{R}_{P}}=\frac{400\times 10000}{400+10000}\] \[=\frac{5000}{13}\Omega \] Total resistance of the circuit                 \[=\frac{5000}{13}+800=\frac{15400}{13}\Omega \] Current in the circuit,                                 \[l=\frac{6}{15400/13}=\frac{37}{7700}A\] Potential difference across voltmeter                 \[=l{{R}_{P}}=\frac{39}{7700}\times \frac{5000}{13}=1.95V\]


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