A) an elliptical path
B) a circular path
C) a parabolic path
D) a straight line path inclined equally to x and y-axis
Correct Answer: B
Solution :
\[x=a\,\sin \omega t\] \[\Rightarrow \] \[\frac{x}{a}=\sin \omega t\] \[y=a\cos \,\,\omega t\] \[\Rightarrow \] \[\frac{y}{a}=\cos \omega t\] \[\frac{{{x}^{2}}}{{{a}^{2}}}+\frac{{{y}^{2}}}{{{a}^{2}}}=1\] \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\] This is the equation of circle, so the particle follows a circular path.
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