A) \[1.8mA\]
B) \[62V,\,\,2\Omega \]
C) \[63V,\,\,1\Omega \]
D) \[61V,\,\,1\Omega \]
Correct Answer: C
Solution :
\[{{l}_{g}}=l\left( \frac{S}{S+G} \right)\] \[\frac{{{l}_{g}}}{l}=\frac{10}{100}=\frac{S}{S+99}\] \[10S=S+99\] \[S=11\Omega \]
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