BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    White light is used to illuminate the two slits in a Youngs double slit experiment. The  separation between the slits is b and the  screen is at a distance d (> b) from the slits,  At a point on the screen directly in front of  one of slits certain wavelength are missing.  One of these missing wavelength for n = 0 is 

    A)  \[\frac{\omega M}{M+m}\]                      

    B)  \[\frac{\omega (M-2M)}{M+2m}\]

    C)  \[\frac{\omega (M+2M)}{M}\]                

    D)  \[\frac{\omega M}{M+2m}\]

    Correct Answer: A

    Solution :

                    In Youngs double slit experiment, path difference is \[\frac{bx}{d}\] and for minima, this path difference should be \[\left( n+\frac{1}{2} \right)\lambda \] \[\therefore \]  \[\frac{bx}{d}=\left( n+\frac{1}{2} \right)\lambda \] here      \[x=\frac{b}{2}\]   and   \[x=0\]                 \[\frac{b}{d}.\frac{b}{1}=\frac{\lambda }{2}\]                 \[\frac{{{b}^{2}}}{d}=\lambda \]


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