A) \[{{10}^{-6}}{{m}^{2}}\]
B) \[{{10}^{29}}\]
C) \[250\times {{10}^{-3}}m/s\]
D) \[25\times {{10}^{-3}}m/s\]
Correct Answer: D
Solution :
We know that, \[n=\frac{t}{T}\] \[t=3000yr.\] \[T=600yr\] \[n=\frac{3000}{600}\] \[=5\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{n}}\] \[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{5}}\] \[=\frac{1}{32}\]
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