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BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    The Edison storage cell is represented as \[{{O}_{2}}\]\[{{U}_{rms}}{{O}_{2}}=2\times {{U}_{rms}}O\] \[{{U}_{rms}}{{O}_{2}}=\frac{1}{2}\times {{U}_{rms}}O\]\[{{U}_{rms}}{{O}_{2}}=\frac{1}{3}\times {{U}_{rms}}\] What is the maximum amount of electrical energy that can be obtained from one mole of \[{{U}_{rms}}{{O}_{2}}={{U}_{rms}}O\]?

    A)  \[Cs-Cl\]                             

    B)  \[CsCl\]

    C)  \[Cl\]                   

    D)  \[62.92%\]

    Correct Answer: B

    Solution :

                    Given,  \[90.71kJ\] and       \[122.55kJ\] \[H{{g}^{2+}}+2C{{l}^{-}}HgC{{l}_{2}},\] \[k=1.65\times {{10}^{3}}\] and        \[H{{g}^{2+}}\] Since, \[2.0m\text{ }mol\]for \[H{{g}^{2+}}\] for \[C{{l}^{-}}\] \[825\times {{10}^{14}}M\]  Redox changes: At anode                 \[1.65\times {{10}^{13}}M\] At cathode \[2.87\times {{10}^{6}}M\] Overall reaction \[6.72\times {{10}^{6}}M\] Hence,         \[{{K}_{f}}\]                                 \[-{{0.360}^{o}}C\] or            \[-{{0.260}^{o}}C\] and        \[2.87\times {{10}^{6}}M\]                 \[672\times {{10}^{6}}M\]                 \[AB\]                 \[{{\log }_{e}}\,\,K=4.0-\frac{2000}{T}\]


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