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BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    In Rosenmund reaction,\[{{\text{V}}_{\text{final}}}\text{=4}{{\text{V}}_{\text{intial}}}\]\[{{V}_{final}}=6{{V}_{\operatorname{int}ial}}\] here,

    A)  promotes catalytic activity of Pd

    B)  removes the \[Ca{{F}_{2}}({{K}_{sp}}=1.7\times {{10}^{-10}})\] formed in the reaction

    C)  deactivates palladium

    D)  activates palladium

    Correct Answer: C

    Solution :

                    \[O=16,Cu=63,N=14\] decreases the activity of Pd. \[1\times {{10}^{-10}}g\]


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