BVP Medical BVP Medical Solved Paper-2014

  • question_answer
    Wave number of a spectral line for a given transition is \[2.0m\text{ }mol\] for \[H{{g}^{2+}}\] then its value for \[C{{l}^{-}}\] (is electronic of \[825\times {{10}^{14}}M\] ) for the same transition is

    A)  \[1.65\times {{10}^{13}}M\]                      

    B)  \[2.87\times {{10}^{6}}M\]

    C)  \[6.72\times {{10}^{6}}M\]                        

    D)  \[{{K}_{f}}\]

    Correct Answer: B

    Solution :

                    \[105.3\] (wave number) \[{{25}^{o}}C\] \[{{V}_{final}}=5{{V}_{initial}}\] \[{{V}_{initial}}>{{V}_{final}}\] \[{{\text{V}}_{\text{final}}}\text{=4}{{\text{V}}_{\text{intial}}}\] Hence,       \[{{V}_{final}}=6{{V}_{\operatorname{int}ial}}\]


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