| I. 1 molecule of oxygen |
| II. 1 atom of nitrogen |
| III. \[-{{0.260}^{o}}C\] molecular weight of oxygen |
| IV. \[2.87\times {{10}^{6}}M\] atomic weight of copper |
A) \[672\times {{10}^{6}}M\]
B) IV < III < II < I
C) \[AB\]
D) \[{{\log }_{e}}\,\,K=4.0-\frac{2000}{T}\]
Correct Answer: A
Solution :
I. 1 molecule of \[Ca{{F}_{2}}({{K}_{sp}}=1.7\times {{10}^{-10}})\] \[{{10}^{-4}}\,M\,C{{a}^{2+}}+{{10}^{-4}}M{{F}^{-}}\] II. 1 atom of \[{{10}^{-2}}\,M\,C{{a}^{2+}}+{{10}^{-3}}M{{F}^{-}}\] III. \[2{{H}^{+}}+2{{e}^{-}}+\frac{1}{2}{{O}_{2}}\xrightarrow{{}}{{H}_{2}}O(l);{{E}^{o}}=+1.23V\] g mol. wt. of oxygen \[F{{e}^{2+}}+2{{e}^{-}}\xrightarrow{{}}Fe(s);\,\,{{E}^{o}}=-0.44V\] IV. \[\Delta G\] atomic weight of copper \[-322\text{ }kJ\text{ }mo{{l}^{-1}}\] \[-161\text{ }kJ\text{ }mo{{l}^{-1}}\] Order of increasing mass is II < I < III < IV
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