A) \[{{I}_{0}}\]
B) \[2{{l}_{0}}{{\cos }^{2}}\left( \frac{\pi y}{\beta } \right)\]
C) \[{{l}_{0}}{{\cos }^{2}}\left( \frac{\pi y}{\beta } \right)\]
D) \[\frac{{{l}_{0}}}{2}{{\cos }^{2}}\left( \frac{2\pi y}{\beta } \right)\]
Correct Answer: C
Solution :
(c.) \[4{{l}_{0}}\] \[3{{l}_{0}}\] \[\frac{{{l}_{0}}}{2}\] Thus \[2{{l}_{0}}\] \[{{I}_{0}}\]
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