BVP Medical BVP Medical Solved Paper-2015

  • question_answer
    There is an infinitely long fixed rod of linear mass density X. A small mass m is revolving around the rod at distance a from the rod with uniform speed due the gravitational pull of the rod. The time period of revolution of m is                

    A)  \[\frac{2\eta }{\lambda }[1-{{e}^{-\lambda t}}]\]                                            

    B)  \[\frac{\eta }{2\lambda }[1-{{e}^{-\lambda t}}]\]

    C)                  \[\frac{\eta }{{{\lambda }^{2}}}[1-{{e}^{-{{\lambda }^{2}}t}}]\]                                 

    D)  \[\frac{\eta }{\lambda }[1-{{e}^{-\lambda t}}]\]

    Correct Answer: C

    Solution :

                    (c.)Balancing forces we can write \[\frac{2G\lambda m}{{{a}^{2}}}=\frac{m{{v}^{2}}}{a}\] \[\Rightarrow \]               \[v=\sqrt{2\lambda G}\]               Thus, time period \[T=\frac{2\pi a}{v}=2\pi \sqrt{\frac{{{a}^{2}}}{2G\lambda }}\]


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