A) \[8H\]
B) \[14H\]
C) \[7H\]
D) \[21H\]
Correct Answer: C
Solution :
(c.)Work done by gravitational force is not equal to elastic potential energy stored in wire, this is due- to the fact that some work has been done against air friction etc, which increases the internal energy of wire \[\left\{ \frac{{{(1+e)}^{2}}}{1+{{e}^{2}}} \right\}\sqrt{\frac{gh}{2}}\] Where, \[\frac{1+{{e}^{2}}}{(1+{{e}^{2}})}\sqrt{\frac{gh}{2}}\] \[\left\{ \frac{{{(1-e)}^{2}}}{1-{{e}^{2}}} \right\}\sqrt{\frac{gh}{2}}\] \[\left\{ \frac{{{(1+e)}^{2}}}{1-{{e}^{2}}} \right\}\sqrt{\frac{gh}{2}}\] \[4\Omega \] Energy released in the form of heat \[2A\]
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