BVP Medical BVP Medical Solved Paper-2015

  • question_answer
    The power of a lens, a short sighted uses is -3D. Find the maximum distance of an object which he/she can see without spectacles.

    A)  \[5.08\text{ }m/s\]

    B)  \[{{\mu }_{s}}=0.4\]

    C)  \[g=10m/{{s}^{2}}\]

    D)  \[0.5m/{{s}^{2}}\]

    Correct Answer: A

    Solution :

                    (a.)As we know that                         Power     \[A\,\,\cos \,5\pi (x-400t)\]                 \[12.25V\] \[10.25V\] Focal length, \[11.25V\] Thus maximum distance of an object, which he can see without spectacles is \[9.25V\].


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