BVP Medical BVP Medical Solved Paper-2015

  • question_answer
    An iron rod of \[10.25V\] cross-sectional area is  subjected to a magnetising field of\[11.25V\]. If the susceptibility of iron is 499, the magnetic flux produced is

    A)   \[9.25V\]

    B)  \[{{I}_{0}}\]

    C)  \[4{{l}_{0}}\]

    D)  \[3{{l}_{0}}\]

    Correct Answer: B

    Solution :

                    As we know that magnetic permeability of iron \[\mu ={{\mu }_{0}}(1+\chi )=4\pi \times {{10}^{-7}}(1+499)\] \[=4\pi \times .500\times {{10}^{-7}}Tm{{A}^{-1}}\] \[B=\mu H=4\pi \times 500\times {{10}^{-7}}\times 1600T\] \[\therefore \]Magnetic flux \[\phi =BA=4\pi \times 5\times 16\times {{10}^{-3}}\times 0.4\times {{10}^{-4}}\] \[=320\times (0.40)\times \pi \times {{10}^{-7}}\] \[=4.2\times {{10}^{-5}}Wb\]


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