BVP Medical BVP Medical Solved Paper-2015

  • question_answer
    The standard electrode potential \[0.15M\] for \[N{{H}_{3}}\] and \[N{{H}_{4}}Cl\] respectively are 0.94 V and -\[Zn+C{{u}^{2+}}\xrightarrow{{}}Z{{n}^{2+}}+Cu\]. The \[C{{u}^{2+}}\] value for \[Cu\] will be

    A)  \[Z{{n}^{2+}}\]                

    B)  \[Zn\]

    C)  \[Zn\]                  

    D)  \[Z{{n}^{2+}}\]

    Correct Answer: A

    Solution :

                    \[II>IV<III<V<I\] \[III<IV<I<V<II\] \[SO_{4}^{2-}\] From the formula,                 \[C{{l}^{-}}\]                 \[C{{a}^{2+}}\]                 \[M{{g}^{2+}}\]                 \[N{{a}_{2}}C{{O}_{3}}\]                 \[CaS{{O}_{4}}+N{{a}_{2}}C{{O}_{3}}\xrightarrow{{}}CaC{{O}_{3}}+N{{a}_{2}}S{{O}_{4}}\]                 \[CaC{{l}_{2}}+N{{a}_{2}}C{{O}_{3}}\xrightarrow{{}}CaC{{O}_{3}}+2NaCl\]                 \[CaC{{O}_{3}}\]                 \[N{{a}_{2}}C{{O}_{3}}\]


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