CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    How much energy is absorbed by 10 kg molecule of an ideal gas, if it expands from an initial pressure of 8 atm to 4 atm at a constant temperature of\[27{}^\circ C\]?

    A)  \[1.728\times {{10}^{7}}J\]        

    B)  \[2.8\times {{10}^{6}}J\]             

    C)         \[5J\]                   

    D)         \[10J\]

    E)  \[15J\]

    Correct Answer: A

    Solution :

    Q = work done by the gas \[Q=\mu RT{{\log }_{e}}\left( \frac{{{p}_{1}}}{{{p}_{2}}} \right)\] \[Q=(10\times 1000\text{ }mol)\times (8.31)\]            \[\times 300\times {{\log }_{e}}\left( \frac{8}{4} \right)\] \[Q={{10}^{4}}\times 8.31\times 300\times 2.302\times 0.301\] \[Q=1.728\times {{10}^{7}}J\]


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