CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    Correct formula of the complex formed in the brown ring test for nitrates is:

    A)  \[FeS{{O}_{4}}NO\]     

    B)         \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]

    C) \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{+}}\]  

    D)  \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{3}}\]

    E)  \[Fe{{({{H}_{2}}O)}_{4}}{{(NO)}_{2}}]\]

    Correct Answer: B

    Solution :

    In the ring test a dark brown ring of\[Fe{{({{H}_{2}}O)}_{5}}NO{{]}^{2+}}SO_{4}^{2-}\]complex formed at the interface between two liquids. \[2NaN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}2NaHS{{O}_{4}}\] \[+2HN{{O}_{3}}\] \[2HN{{O}_{3}}+6FeS{{O}_{4}}+3{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\]                                 \[3F{{e}_{2}}{{(S{{O}_{4}})}_{3}}+2NO+4{{H}_{2}}O\] \[[Fe{{({{H}_{2}}O)}_{6}}]S{{O}_{4}}+NO\xrightarrow{{}}\]                                 \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}SO_{4}^{2-}+{{H}_{2}}O\]


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