A) 0.13893
B) 1.3843
C) 1.3893
D) 0.13843
E) 1.3869
Correct Answer: C
Solution :
\[f(x)={{\log }_{e}}x\] where\[x=4\]and\[\Delta x=4.01-4=0.01\] Now, \[f(x)=\frac{1}{x}\] \[\therefore \] \[f(x+\Delta x)=f(x)+f(x)\Delta x\] \[={{\log }_{e}}4+\frac{1}{4}\times 0.01\] \[=1.3868+0.0025\] \[=1.3893\]You need to login to perform this action.
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