A) 23.077%
B) 30.77%
C) 2.3077%
D) 0.23077%
E) 46.154%
Correct Answer: A
Solution :
Let \[{{H}_{2}}O=x\text{ }mol=18x\text{ }g\] Urea \[=x\text{ }mol=60\text{ }xg\] Total mass of the solution \[=18x+60x\] \[=78xg\] Hence, mass % of urea\[=\frac{18x}{78x}\times 100\] \[=23.077%\]
You need to login to perform this action.
You will be redirected in
3 sec
