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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    A short bar magnet with a magnetic moment of\[0.5\text{ }J/T\]is placed in a uniform external magnetic field of 0.16 T in such a way that the magnetic moment vector is anti-parallel to the direction of the magnetic field. The potential energy of the bar magnet is:

    A)  0.32 J                                   

    B)  0.16 J   

    C)         0.08 J                   

    D)         \[-0.08J\]

    E)  \[-0.32J\]

    Correct Answer: C

    Solution :

    The potential energy is given by \[U=-M.B\] Given   \[M=0.5\text{ }J/T,\text{ }B=0.16\text{ }T.\] \[\therefore \] \[U=-0.5\times 0.16\] \[U=0.08\text{ }J\]


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