A) \[\frac{\pi }{2}\]
B) \[0\]
C) \[\frac{\pi }{3}\]
D) \[\frac{\pi }{4}\]
E) \[\frac{\pi }{6}\]
Correct Answer: A
Solution :
Since, \[\tan \theta =\left( \frac{1-{{r}^{2}}}{r} \right)=\frac{{{\sigma }_{x}}{{\sigma }_{y}}}{\sigma _{x}^{2}+\sigma _{y}^{2}}\] Now, if\[r=0,\]then\[\tan \theta =\infty \] \[\Rightarrow \,\,\,\,\,\,\,\,\,\,\,\,\,\theta =\frac{\pi }{2}\]
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