CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    A transformer of 100% efficiency has 200 turns in the primary and 40000 turns in secondary is connected to a 220 V main supply and secondary feeds to a\[100\,k\Omega \]resistance. The  Potential difference per turn is respectively:

    A)  \[1.1\,V\]         

    B)         \[25V\]               

    C)         \[18\,V\]            

    D)         \[11\,V\]

    E)  \[35V\]

    Correct Answer: A

    Solution :

    From transformer ratio \[\frac{{{V}_{s}}}{{{V}_{p}}}=\frac{{{N}_{s}}}{{{N}_{p}}}\] \[\Rightarrow \]               \[{{V}_{s}}=\frac{{{V}_{p}}\times {{N}_{s}}}{{{N}_{p}}}\] \[=\frac{220V\times 40000}{200}=44000V\] Potential difference per turn is                 \[\frac{{{V}_{s}}}{{{N}_{s}}}=\frac{44000V}{40000}=1.1V\]


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