A) \[10I\]and zero
B) \[10I\]and\[8I\]
C) \[10I\]and\[4I\]
D) \[16I\]and\[4I\]
E) \[16I\]and zero
Correct Answer: D
Solution :
The ratio of maximum to minimum intensity is \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{(\sqrt{{{I}_{1}}}+\sqrt{{{I}_{2}}})}^{2}}}{{{(\sqrt{{{I}_{1}}}-\sqrt{{{I}_{2}}})}^{2}}}=\frac{{{(1+3)}^{2}}}{(1-3)}=\frac{{{4}^{2}}}{{{2}^{2}}}\] \[=\frac{16}{4}\]
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