A) \[(-14,14)\]
B) \[(-12,12)\]
C) \[(-16,16)\]
D) \[(-21,21)\]
E) \[(0,\text{ }a)\]
Correct Answer: B
Solution :
\[\frac{dy}{dx}=3{{x}^{2}}-2ax+48>0\] (\[\because \]y is an increasing function) \[\therefore \]Discriminant, \[D<0\,\,4{{a}^{2}}-4\times 3\times 48<0\] \[\Rightarrow \]\[{{a}^{2}}-144<0\Rightarrow a\in (-12,12)\]
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