question_answer

There are\[(n+1)\]white and\[(n+1)\]black balls, each set of numbered 1 to\[n+1\]. The number of ways the balls can be arranged in a row so that adjacent balls are of different colours, is:

A)  \[(2n+1)!\]        

B)                         \[2(2n)!\]                          

C)         \[2[(n+1)!]\]                    

D)         \[2{{[(n+1)!]}^{2}}\]

E)         \[{{[(n+1)!]}^{2}}\]