A) \[\frac{1}{r}\]
B) \[\frac{1}{{{r}^{2}}}\]
C) \[\frac{1}{{{r}^{3}}}\]
D) \[\frac{1}{{{r}^{4}}}\]
E) \[\frac{1}{{{r}^{6}}}\]
Correct Answer: C
Solution :
For a dipole of length\[2l\] \[E=\frac{1}{4\pi {{\varepsilon }_{0}}K}.\frac{2pr}{{{({{r}^{2}}-{{l}^{2}})}^{2}}}\] When\[(l<<r),\]then\[{{l}^{2}}\]may be neglected in comparison to\[{{r}^{2}}\]. \[\therefore \] \[E=\frac{1}{4\pi {{\varepsilon }_{0}}K}\frac{2pr}{{{r}^{4}}}=\frac{1}{4\pi {{\varepsilon }_{0}}K}=\frac{2p}{{{r}^{3}}}N/C\] \[\Rightarrow \] \[E\propto \frac{1}{{{r}^{3}}}\]You need to login to perform this action.
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