CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    At the top of the trajectory of a projectile, thrown at an angle of projection\[\theta <90{}^\circ ,\] its:

    A)  velocity is zero

    B)  velocity is parallel to the direction of acceleration

    C)  velocity is anti-parallel to the direction of acceleration

    D)  acceleration is zero

    E)  velocity is perpendicular to the direction of acceleration

    Correct Answer: E

    Solution :

    At the highest point (P) of the project trajectory, vertical component of velocity is zero, only horizontal component exists which is perpendicular to the direction of acceleration.


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