A) \[1.2\times {{10}^{-8}}J\]
B) \[2.4\times {{10}^{-8}}J\]
C) \[5.0\,\times {{10}^{-8}}J\]
D) \[1.2\times {{10}^{-6}}J\]
E) \[5.0\times {{10}^{-6}}J\]
Correct Answer: C
Solution :
The energy stored in capacitor is given by \[E=\frac{1}{2}C{{V}^{2}}\] Resultant capacitance \[C={{C}_{1}}+{{C}_{2}}=4+6=10\,pF\] \[E=\frac{1}{2}\times 10\times {{10}^{-12}}\times {{(100)}^{2}}\] \[(1\,pF={{10}^{-12}}F)\] \[=5\times {{10}^{-8}}J\]
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