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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    A disc, initially at rest, starts rotating about its own axis, with a constant angular acceleration of\[0.2\text{ }rad/{{s}^{2}}\]. The time taken by the disc to rotate by 10 rad is (in seconds):

    A)  7.07                      

    B)         10

    C)  14.14                   

    D)         100

    E)  200

    Correct Answer: B

    Solution :

    From the equation, \[\theta ={{\omega }_{0}}t+\frac{1}{2}\alpha {{t}^{2}}\] Given, \[a+0.2\text{ }rad/{{s}^{2}},\text{ }{{\omega }_{0}}=0,\text{ }\theta =10\text{ }rad\]. \[\Rightarrow \]               \[10=\frac{1}{2}(0.2){{t}^{2}}\] \[\Rightarrow \]               \[{{t}^{2}}=100\] \[\Rightarrow \]               \[t=10\,s\]


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