CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    A thin disc is rotating with a constant angular velocity about its own axis. A is a point on the rim of the disc and B is a point half-way between the rim and the centre. The ratio of the velocity at A to that at B is:

    A)  \[1:4\]                 

    B)         \[1:2\]

    C)  \[1:1\]                 

    D)         \[2:1\]

    E)  \[4:1\]

    Correct Answer: D

    Solution :

    The relation between linear velocity v and angular velocity\[\omega \]is \[v=r\omega \] \[\Rightarrow \]               \[\omega =\frac{v}{r}\] Given,   \[{{\omega }_{1}}={{\omega }_{2}}\] \[\Rightarrow \]               \[\frac{{{v}_{1}}}{{{r}_{1}}}=\frac{{{v}_{2}}}{{{r}_{2}}}\] \[\Rightarrow \]               \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{{{r}_{1}}}{{{r}_{2}}}\] where, \[{{r}_{1}}=r,{{r}_{2}}=\frac{r}{2}\] \[\therefore \]  \[\frac{{{v}_{A}}}{{{v}_{B}}}=\frac{1}{1/2}=\frac{2}{1}\]


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