CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    A simple pendulum has a time period of 1 s. In order to increase the time period to 2 s:

    A)  the mass of the bob should be doubled

    B)  the length of the pendulum should be doubled

    C)  the length of the pendulum should be increased by a factor of 4

    D)  the length of the pendulum should be decreased a factor of 4

    E)  both the mass and the length of the pendulum should be doubled

    Correct Answer: C

    Solution :

    \[T=2\pi \sqrt{\frac{l}{g}}\] Given,   \[{{T}_{1}}=1s,{{l}_{1}}=l,{{T}_{2}}=2s\] \[\therefore \]  \[\frac{{{T}_{1}}}{{{T}_{2}}}=\sqrt{\frac{{{l}_{1}}}{{{l}_{2}}}}\] \[\Rightarrow \]               \[\frac{1}{2}=\sqrt{\frac{{{l}_{1}}}{{{l}_{2}}}}\] \[\Rightarrow \]               \[{{l}_{2}}=4{{l}_{1}}\] Hence, length of pendulum should be increased by a factor of 4.


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