A) \[144{{\pi }^{2}}m/{{s}^{2}}\]
B) \[12m/{{s}^{2}}\]
C) \[11m/{{s}^{2}}\]
D) \[169m/{{s}^{2}}\]
E) none of these
Correct Answer: A
Solution :
The maximum acceleration of SHM. \[\alpha ={{\omega }^{2}}a\] where \[\omega =2\pi \,n\] \[\therefore \]\[\alpha ={{(2\pi n)}^{2}}a=4{{\pi }^{2}}\times {{(60)}^{2}}\times (0.01)\] \[\Rightarrow \] \[\alpha =144\,{{\pi }^{2}}m/s\]
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