A) \[2.8\times {{10}^{5}}N/{{m}^{2}}\]
B) \[1.72\times {{10}^{8}}N/{{m}^{2}}\]
C) \[6.3\times {{10}^{3}}N/{{m}^{2}}\]
D) \[8\times {{10}^{-6}}N/{{m}^{2}}\]
E) \[1.57\times {{10}^{4}}N/{{m}^{2}}\]
Correct Answer: B
Solution :
\[B=\frac{Change\text{ }in\text{ }pressure}{Volume\text{ }strain}=\frac{p}{\gamma ({{t}_{2}}-{{t}_{1}})}\] \[\therefore \] \[p={{B}_{\gamma }}({{t}_{2}}-{{t}_{1}})\] Given, \[B=3.6\times {{10}^{11}}N/{{m}^{2}},\] \[\gamma =3\alpha =3\times 8\times {{10}^{-6}}=24\times {{10}^{-6}}/{}^\circ C\] \[{{t}_{2}}-{{t}_{1}}=70-50=20{}^\circ C\] \[\therefore \]\[p=(3.6\times {{10}^{11}})(24\times {{10}^{-6}})(20)\] \[=1.728\times {{10}^{8}}N/{{m}^{2}}\]
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