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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    Given that the surface tension of water is 75 dyne/cm, its density 1 g/cc and angle of contact zero, the height to which water rises in a capillary tube of 1 mm diameter is: (take\[g=10\text{ }m/{{s}^{2}}\])

    A)  9.0 cm                 

    B)         7.5 cm

    C)  6.0 cm                 

    D)         3.0cm

    E)  1.5 cm

    Correct Answer: D

    Solution :

    Height to which water rises in the capillary tube is \[h=\frac{2T\cos \theta }{r\rho g}\] Given,\[T=75\text{ }dyne/cm,\text{ }\theta =0{}^\circ ,\text{ }r=\frac{1}{2}\times 10\text{ }cm.\] \[g=10\text{ }m/{{s}^{2}},\text{ }\rho =1\text{ }g/cc.\] \[\therefore \]  \[h=\frac{2\times 75\times \cos 0{}^\circ \times 2}{10\times 10}=3cm\]


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