CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The distance between the carbon atom and the oxygen atom in a carbon monoxide molecule is \[1.1\overset{\text{o}}{\mathop{\text{A}}}\,\]. Given, mass of carbon atom is 12 amu and mass of oxygen atom is 16 amu. Calculate the position of the centre of mass of the carbon monoxide molecule:

    A)  \[6.3\overset{\text{o}}{\mathop{\text{A}}}\,\] from the carbon atom

    B)  \[1\overset{\text{o}}{\mathop{\text{A}}}\,\] from the oxygen atom

    C)  \[0.63\overset{\text{o}}{\mathop{\text{A}}}\,\] from the carbon atom

    D) \[0.12\overset{\text{o}}{\mathop{\text{A}}}\,\] from the oxygen atom

    E) \[0.16\overset{\text{o}}{\mathop{\text{A}}}\,\] from the carbon atom

    Correct Answer: C

    Solution :

    Let\[{{x}_{cm}}\]be distance of centre of mass from C-atom \[{{x}_{cm}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}}{{{m}_{1}}+{{m}_{2}}}=\frac{12\times 0+16\times 1.1}{12+16}\] \[=0.63\overset{\text{o}}{\mathop{\text{A}}}\,\]


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