A) 8 g of methane
B) \[16800\text{ }c{{m}^{3}}\]or carbon dioxide at STP
C) 14 g of nitrogen
D) 4 g of oxygen
E) 64 g of sulphur dioxide
Correct Answer: E
Solution :
Number of moles \[\frac{\text{wt}\text{.}\,\text{of}\,\text{substance}\,\text{in}\,\text{grams}}{\text{gram}\,\text{molecular}\,\text{wt}\text{.}}\] With the help of above formula we calculate number of moles for all the cases. It comes highest for 64 g of\[S{{O}_{2}}\]as, Mol. wt. of\[S{{O}_{2}}=32+32=64\text{ }g\] Gram mol. wt. = 64 g \[\therefore \]64 g or 1 mol of\[S{{O}_{2}}\]contains \[=6.023\times {{10}^{23}}\]molecules
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