CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The distance of the point\[(2,1,-1)\]from the plane\[x-2y+4z=9\]is:

    A)  \[\sqrt{\frac{13}{21}}\]

    B)                         \[\frac{23}{21}\]                             

    C)  \[\frac{13}{\sqrt{21}}\]

    D)         \[\frac{\sqrt{13}}{21}\]

    E)  None of these

    Correct Answer: C

    Solution :

                    The distance of the point\[(2,1,-1)\]from the plane\[x-2y+4z=9\] \[\left| \frac{(1\times 2)+(-2)(1)+4(-1)-9}{\sqrt{{{1}^{2}}+{{(-2)}^{2}}+{{4}^{2}}}} \right|\]                 \[=\left| \frac{2-2-4-9}{\sqrt{1+4+16}} \right|\]                 \[=\frac{13}{\sqrt{21}}\]


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