A) 0
B) \[-\,41\]
C) \[\frac{-17}{2}\]
D) 41
E) \[\frac{17}{4}\]
Correct Answer: D
Solution :
\[\because \]Circle\[{{x}^{2}}+{{y}^{2}}-17x+2fy+c=0\]passes through (3, 1), (14, 1) and (11, 5), then \[2f+c=41\] ...(i) \[2f+c=41\] ...(ii) and \[10f+c=41\] ...(iii) On solving Eqs. (i) and (iii), we get\[c=41,\]and\[f=0\]
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