2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    25 tuning forks are arranged in series in the order of decreasing frequency. Any two successive forks produce 3 beats/s. If the frequency of the first tuning fork is the octave of the last fork, then the frequency of the 21st fork is:

    A)  72 Hz                   

    B)         288 Hz 

    C)         84 Hz                   

    D)         87 Hz

    E)  144 Hz

    Correct Answer: C

    Solution :

    If n is the frequency of last fork then frequency of first fork be\[2n\]. So, \[2n-(25-1)\times 3=n\] \[\Rightarrow \]               \[n=72\,Hz\] 21st fork frequency \[=144-(21-1)(3)\]         \[=84\text{ }Hz\]


You need to login to perform this action.
You will be redirected in 3 sec spinner