A) \[\sin \alpha \]
B) \[\cos \alpha \]
C) \[\sin \beta \]
D) \[\cos 2\beta \]
E) \[\sin 2\alpha \]
Correct Answer: C
Solution :
\[\because \] \[cot(\alpha +\beta )=0\] \[\Rightarrow \] \[\cot (\alpha +\beta )=\cot 0{}^\circ \] \[\Rightarrow \] \[\alpha +\beta =0{}^\circ \] \[\therefore \,\,\,\,\,\,\,\,\,\sin (\alpha +2\beta )\,=\sin (\alpha +\beta +\beta )\] \[=\sin \beta \]
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