A) \[\frac{1}{4}\]
B) \[\frac{1}{24}\]
C) \[\frac{23}{24}\]
D) \[\frac{3}{4}\]
E) \[1\]
Correct Answer: D
Solution :
The probability that the problem cannot solve by any one of the student \[=\left( 1-\frac{1}{2} \right)\left( 1-\frac{1}{3} \right)\left( 1-\frac{1}{4} \right)\] \[=\frac{1}{2}\times \frac{2}{3}\times \frac{3}{4}=\frac{1}{4}\] \[\therefore \]The probability that the problem will be solved at least by one\[=1-\frac{1}{4}=\frac{3}{4}\].
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