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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    If the mean of numbers\[27+x,\text{ }31+x,\]\[89+x,\] \[107+x,\text{ }156+x\]is 82, then the mean of \[130+x,\text{ }126+x,\text{ }68+x,\text{ }50+x,\text{ }1+x\]is:

    A)  79                         

    B)         157

    C)  82                         

    D)         80

    E)  75

    Correct Answer: E

    Solution :

    According to question , \[82=\frac{\left( \begin{align}   & 27+x+31+x+89+x+107+x \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+156+x \\ \end{align} \right)}{5}\] \[\Rightarrow \]               \[410=410+5x\] \[\Rightarrow \]               \[5x=0\] \[\Rightarrow \]               \[x=0\] \[\therefore \]Required mean \[=\frac{\left( \begin{align}   & 130+x+126+x+68+x \\  & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+50+x+1+x \\ \end{align} \right)}{5}\] \[=\frac{130+126+68+50+1}{5}\] \[=\frac{375}{5}=75\]


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