A) \[-1\]
B) 2
C) \[-3\]
D) \[-2\]
E) 1
Correct Answer: E
Solution :
\[\because \]\[f(x)\]is continuous at\[x=1,\] \[\therefore \] \[\underset{h\to {{0}^{+}}}{\mathop{\lim }}\,f(1+h)=f(1)\] \[\Rightarrow \] \[\underset{h\to 0}{\mathop{\lim }}\,3-a{{(1+h)}^{2}}=2\] \[\Rightarrow \] \[3-a{{(1+0)}^{2}}=2\] \[\Rightarrow \] \[a=1\]
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