A) \[n(A)+n(B)\]
B) \[n(A)+n(B)-n(A\cap B)\]
C) \[n(A)+n(B)+n(A\cap B)\]
D) \[n(A)\,n(B)\]
E) \[n(A)-n(B)\]
Correct Answer: B
Solution :
\[\because \]A and B are not disjoint sets. \[\therefore \] \[n(A\cup B)=n(A)+n(B)-n(A\cap B)\]
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