2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The domain of\[{{\sin }^{-1}}\left( \frac{2x+1}{3} \right)\]is:

    A)  \[(2,-1)\]            

    B)         \[[-2,1]\]

    C)  R                           

    D)         \[(-1,1)\]

    E)  \[(-2,\text{ }0)\]

    Correct Answer: B

    Solution :

    Let \[y={{\sin }^{-1}}\left( \frac{2x+1}{3} \right)\] \[\therefore \] \[-1\le \frac{2x+1}{3}\le 1\]         \[(\because -1\le {{\sin }^{-1}}x\le 1)\] \[\Rightarrow \]               \[-3\le 2x+1\le 3\] \[\Rightarrow \]               \[-4\le 2x\le 2\] \[\Rightarrow \]               \[-2\le x\le 1\] \[\therefore \]  \[x\in [-2,1]\]


You need to login to perform this action.
You will be redirected in 3 sec spinner