CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    If \[1,\omega ,{{\omega }^{2}}\]are cube roots of unity, then \[{{(1+\omega )}^{3}}-1{{(1+{{\omega }^{2}})}^{3}}\]is:

    A)  0                            

    B)         \[-1\]

    C)  \[\omega \]                      

    D)         2

    E)  \[-2\]

    Correct Answer: A

    Solution :

    \[{{(1+\omega )}^{3}}-{{(1+{{\omega }^{2}})}^{3}}\] \[={{(-{{\omega }^{2}})}^{3}}-{{(-\omega )}^{3}}\] \[=-{{(-{{\omega }^{3}})}^{2}}+{{(\omega )}^{3}}=-1+1=0\]


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