CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    \[{{\mu }_{0}}\]denotes absolute permeability and \[{{E}_{0}}\]denotes the absolute permittivity of free space. Then the velocity of electromagnetic waves in free space is:

    A)  \[{{\mu }_{0}}{{\varepsilon }_{0}}\]                                       

    B)  \[\sqrt{{{\mu }_{0}}/{{\varepsilon }_{0}}}\]                        

    C)  \[\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}\]          

    D)         \[{{\varepsilon }_{0}}/{{\mu }_{0}}\]

    E)  \[1/\sqrt{{{\mu }_{0}}/{{\varepsilon }_{0}}}\]

    Correct Answer: E

    Solution :

    \[v=\frac{1}{\sqrt{{{\varepsilon }_{0}}{{\mu }_{0}}}}\]


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